Currently teaching physics and math at Freie Schule Anne Sophie in Berlin Germany.


16 thoughts on “About

  1. Hi Brian, I just recently watch your video about finding; total volt. Equivalent resistance (Can you also call it Total resistance?), Total current, voltage drop across each resistor and what is current or total current through each resistor?

    How come you put ohms law V=IxR at the Voltage Drop on the series circuit video but fail to do so on the parallel circuit video and instead putting in next to current through each resistor? Some simple explanation would be good.


  2. Hi! Your videos are so helpful! I use them for every topic! But I just realized you don’t have a video on momentum and collision for Physics. Could you make one? (Unless you already have it – but its under a different name – please disregard this)


    1. You are not the first to ask about this topic, but unfornuately I do not have any videos covering monmetum and collisions. It is on my list but I probably will not be able to get to it in the near future.


  3. Thank you for your videos. Your chemical reactions have been very clarifying to me minus a few questions I have. Your very helpful. I would love to have a way to get the moles worked out in my head the right way- gee, I try so hard but they always confuse me.


  4. Hey!
    Why do you have a website if it just leads us back to the youtube videos? I only saw that you had a website through YouTube, then it tells me to go right back!
    Super helpful, as a Chemistry Student struggling to understand Calorimetry Problems. Thank you!


  5. When a body is thrown up height is upward and mg is downward so work done is minus mgh but there is a gain in potential energy so how is it possible? If work done is negative of potential energy then how possible in this case plz explain . (External work and field work with constant velocity )


    1. Work is calculated as W = f x d x cos(theta). When you move something up, the displacement (direction of motion) and the direction of the force you apply are in the same direction, up, and are parallel to each other. The angle between parallel lines is zero degrees and the cos of 0 degrees = 1. So when you move something up you do positive work and the object gains an amount of potential energy equal to the work you do on the object.

      When you move something down you do negative work on the object and it loses potential energy. Does that help?


  6. Hi sir recently I watched your kinematics vedios now it is so simple for me but I need some more examples feeply


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